9x^2-46x-48=0

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Solution for 9x^2-46x-48=0 equation:



9x^2-46x-48=0
a = 9; b = -46; c = -48;
Δ = b2-4ac
Δ = -462-4·9·(-48)
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3844}=62$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-62}{2*9}=\frac{-16}{18} =-8/9 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+62}{2*9}=\frac{108}{18} =6 $

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